Problem | Solution |

\(\begin{align}
& y = x^3 - 3 \\[0.5em]
& [-3, 3]
\end{align}\) |
Ms Shaws Math Class70637 |

\(\begin{align}
& f(t) = t + \cot\left(\dfrac{1}{2}t\right)\\[0.5em]
& \left[-\dfrac{\pi}{4}, \dfrac{7\pi}{4}\right]
\end{align}\) |
Ms Shaws Math Class70638 |

\(\begin{align}
& f(t) = 2\cos t + \sin 2t \\[0.5em]
& \left[0, \dfrac{\pi}{2}\right]
\end{align}\) |
Ms Shaws Math Class70639 |

\(\begin{align}
& f(x) = \dfrac{x}{x^2 - x + 1} \\[0.5em]
& [0, 3]
\end{align}\) |
Ms Shaws Math Class70641 |

\(\begin{align}
& f(t) = t\sqrt{4 - t^2} \\[0.5em]
& [-1, 2]
\end{align}\) |
Ms Shaws Math Class70642 |

\(\begin{align}
& f(x) = x^3 - 6x^2 + 5 \\[0.5em]
& [-3, 5]
\end{align}\) |
Ms Shaws Math Class70643 |

\(\begin{align}
& f(x) = 2x^3 - 3x^2 - 12x + 1 \\[0.5em]
& [-2, 3]
\end{align}\) |
Ms Shaws Math Class70644 |

\(\begin{align}
& f(x) = \left(x^2 - 1\right)^3 \\[0.5em]
& [-1, 2]
\end{align}\) |
Ms Shaws Math Class70645 |

\(\begin{align}
& f(x) = 5 + 54x - 2x^3 \\[0.5em]
& [0, 4]
\end{align}\) |
Ms Shaws Math Class70646 |

\(\begin{align}
& f(x) = 12 + 4x - x^2 \\[0.5em]
& [0, 5]
\end{align}\) |
Ms Shaws Math Class70647 |