\(2^2 = 2^x\)
\(x = 2\)
\(27^5 = 27^x\)
\(x = 5\)
\(2^{2x} = 2^6\)
\(x = 3\)
\(3^x = 3^2\)
\(x = 2\)
\(4^{2x - 1} = 4\)
\(x = 1\)
\(4^{2x - 3} = 4^{x + 7}\)
\(x = 10\)
\(9^{x - 2} = 9^{3x}\)
\(x = -1\)
\(3^x = 9\)
\(x = 2\)
\(2^x = 4\)
\(x = 2\)
\(8^x = 2\)
\(x = \dfrac{2}{3}\)
\(\left(\dfrac{1}{3}\right)^x = 27\)
\(x = -3\)
\(3^x = 243\)
\(x = 5\)
\(4^x = 2^8\)
\(x = 4\)
\(2^x = 8^3\)
\(x = 9\)
\(4^x = 16\)
\(x = 2\)
\(4^x = \dfrac{1}{16}\)
\(x = -2\)
\(\left(\dfrac{1}{2}\right)^x = 32\)
\(x = -5\)
\(\left(\dfrac{2}{3}\right)^x = \dfrac{4}{9}\)
\(x = 2\)
\(9^x = 27\)
\(x = \dfrac{3}{2}\)
\(2^{2x - 1} = 8\)
\(x = 2\)
\(125^{2x + 1} = 25\)
\(x = \dfrac{-1}{6}\)
\(8^{x + 3} = 16^{x - 1}\)
\(x = 7\)
\(16^{x - 3} = 32\)
\(x = \dfrac{17}{4}\)
\(16^{x - 1} = 64\)
\(x = \dfrac{5}{2}\)
Solve 16^(x-1) = 64 an Exponential Equation using the One-To-One Property Equating Bases
Prof. Redden
\(10^{x + 1} = 1000\)
\(x = 2\)
\(2^{x + 3} = 256\)
\(x = 5\)
\(4^{3x - 3} = 8^{4x - 4}\)
\(x = 1\)
\(3^{2x + 4} = 27\)
\(x = \dfrac{-1}{2}\)
\(64^{x + 1} = 4\)
\(x = \dfrac{-1}{2}\)
\(3^{x + 2} = 27^{2x}\)
\(x = \dfrac{2}{5}\)
\(4^{x - 2} = 16^{2x + 5}\)
\(x = -4\)
\(4^{x - 5} = 16^{2x - 31}\)
\(x = 19\)
\(5^{x - 4} = 25^{x - 6}\)
\(x = 8\)
\(5^{x + 1} = 125^x\)
\(x = \dfrac{1}{2}\)
\(100^{7x + 1} = 1000^{3x - 2}\)
\(x = \dfrac{-8}{5}\)
\(8^{x - 1} = 32^{3x - 2}\)
\(x = \dfrac{7}{12}\)
\(25^{2x + 3} = 25^{5x - 9}\)
\(x = 4\)
\(27^{x - 2} = 9^x\)
\(x = 6\)
\(9^{2x - 1} = 3^{3x + 3}\)
\(x = 5\)
\(125^{3x - 4} = 25^{4x + 2}\)
\(x = 16\)
\(9^{-x + 5} = 27^{6x - 10}\)
\(x = 2\)
\(5^{5x} = 125^{x + 2}\)
\(x = 3\)
\(9^{2x - 1} = 3^{6x}\)
\(x = -1\)
\(2^{x - 3} = 32\)
\(x = 8\)
\(25^{x + 3} = 5\)
\(x = \dfrac{-5}{2}\)
\(9^{-x + 5} = 27^{6x - 10}\)
\(x = 2\)
\(2 \cdot 3^{2x - 4} = 18\)
\(x = 3\)
\(16^x + 2 = 6\)
\(x = \dfrac{1}{2}\)
\(64^{2x} - 7 = 1\)
\(x = \dfrac{1}{4}\)
\(40 \cdot \left(\dfrac{1}{2}\right)^{x/4} = 5\)
\(x = 12\)
\(40 \cdot \left(\dfrac{1}{4}\right)^{x/3} = 5\)
\(x = \dfrac{9}{2}\)
\(20 \cdot \left(\dfrac{1}{2}\right)^{x/3} = 5\)
\(x = 6\)
\(\left(\dfrac{2}{3}\right)^x = \dfrac{4}{9}\)
\(x = 2\)
\(7^{3t} = \left(\dfrac{1}{49}\right)^{t - 5}\)
\(t = 2\)
How to Solve Exponential Equations with the Same Base FRACTIONS | THIS will HELP you SOLVE!
iZAP Math
\(\left(\dfrac{1}{32}\right)^{x - 1} = 8^x\)
\(x = \dfrac{5}{8}\)
\(\left(\dfrac{1}{27}\right)^{2x - 1} = 9^{x + 1}\)
\(x = \dfrac{1}{8}\)
\(9^x\left(\dfrac{1}{3}\right)^{x + 2} = 27\left(3^x\right)^{-2}\)
\(x = \dfrac{5}{3}\)
